Question

Specific Heat Material Copper Aluminum Gold Pyrex Specific Heat (J/g °C) 0.385 0.902 0.129 0.75 Material Water Ice Olive Oil Air Specific Heat (1/g °C) 4.18 2.01 2.38 1.00 If the same amount of heat was applied to a vessel containing 100.0 g of water and 100.0 g of Olive Oil, which would get hotter? Why? If you had a 1.0 kg pot made of each metal, which pot would allow you to heat water to boiling more quickly? Why? How much heat would it take to raise the temperature of 100.0 g of water from 20.0°C to 100.0 °C? (Ignore the pot)

Answer 1

Step-by-step explanation:

• It is known that the amount of heat necessary to raise the temperature of 1 gram of a substance by
  `1^(o)C` is known as specific heat.

Since, q =
`mC \Delta T`

So, larger is the specific heat of a substance less will be the change in its temperature.

Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.

• Similarly, the specific heat of gold is lesser than the given materials or metals. Hence, gold will requires less heat to rise its temperature.

As a result, water present in gold will heat readily.

• As the relation between heat and specific heat is as follows.

q =
`mC \Delta T`

Therefore, calculate the amount of heat required by the water as follows.

q =
`mC \Delta T`

=
`100 g * 4.18 J/g^(o)C * (100 - 20)^(o)C`

= 33440 J

or, = 33.44 kJ (as 1 kJ = 1000 J)

Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from
`20.0^(o)C` to
`100.0^(o)C`.