Question

A chemist needs to know the concentration of some NaOH that is in the laboratory. To find this out, she titrates a 50.0 mL sample of the solution with 3.5 M HCl. If it takes 34.3 mL of the HCl to reach the titration endpoint, what is the concentration of the NaOH solution?

Answer 1

Answer: 2.4 M

Step-by-step explanation:

According to the neutralization law,

`n_1M_1V_1=n_2M_2V_2`

where,

`M_1` = molarity of
`Hl` solution = 3.5 M

`V_1` = volume of
`HCl` solution = 34.3 ml

`M_2` = molarity of
`NaOH` solution = ?

`V_2` = volume of
`NaOH` solution = 50 ml

`n_1` = valency of
`HCl` = 1

`n_2` = valency of
`NaOH` = 1

`1* 3.5M* 34.3=1* M_2* 50`

`M_2=2.4`

Therefore, the concentration of NaOH solution is 2.4 M.