Question

A chemist reacts 35 g of MgCl, with excess KOH according

to the reaction below. How much Mg(OH)2 would be
produced if the reaction goes to completion?
MgCl2 + 2KOH – Mg(OH)2 + 2KCI

Answer 1

Mass = 21.58 g

Step-by-step explanation:

Given data:

Mass of MgCl₂ = 35 g

Mass of Mg(OH)₂ produced = ?

Solution:

Chemical equation:

MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

Number of moles of MgCl₂:

Number of moles = mass/molar mass

Number of moles = 35 g/ 95.2 g/mol

Number of moles = 0.37 mol

now we will compare the moles of MgCl₂ and Mg(OH)₂

MgCl₂ : Mg(OH)₂

1 : 1

0.37 : 0.37

Mass of Mg(OH)₂ :

Mass = number of moles × molar mass

Mass = 0.37 mol × 58.32 g/mol

Mass = 21.58 g