Question

In an old-fashioned amusement park ride, passengers stand inside a 3.0-m-tall, 5.0-m-diameter hollow steel cylinder with their backs against the wall. The cylinder begins to rotate about a vertical axis. Then the floor on which the passengers are standing suddenly drops away! If all goes well, the passengers will stick to the wall and not slide. Clothing has a static coefficient of friction against steel in the range 0.60 to 1.0 and a kinetic coefficient in the range 0.40 to 0.70.What is the minimum rotational frequency, in rpm, for which the ride is safe?

Answer 1

Answer:2.55 rad/s

Step-by-step explanation:

Given

Diameter of ride=5 m

radius(r)=2.5 m

Static friction coefficient range=0.60-1

Here Frictional force will balance weight

And limiting frictional force is provided by Centripetal force

`f=\mu N=\mu m\omega ^2\cdot r`

weight of object=mg

Equating two

f=mg

`\mu m\omega ^2\cdot r=mg`

`\omega ^2=(g)/(\mu r)`

`\omega =\sqrt{(g)/(\mu r)}`

`\omega =2.55 rad/sec`