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If an integer n has three unique prime divisors, then it follows that the largest prime divisor of n is less than or equal to cube root of n. True or False?

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Answer:

False

Explanation:

Lets call the three prime divisors of n p, q, and r, being r the largest, we know:


n=q * p * r

Now, if


q * p < r

then


n < r * r = r^2

So:


√(n) < √(r^2) = r

Also, for every natural greater than one, we know:


\sqrt[3]{n}<√(n)

so


\sqrt[3]{n}<√(n) < r

from which:


\sqrt[3]{n} < r

So, we see, this means the preposition is false, we can find a particular counterexample:

q=2

p=3

p*q = 6

We need to choose a prime greater than 6

r=7

n= 2 * 3 *7 = 42


\sqrt[3]{42} = 3.4760 < 7

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