Question

Damarcus and Xavier went to the arcade to play their two favorite games. Damarcus played 4 rounds of game 1 and 6 rounds of game 2 for $18.00. Xavier played 5 rounds of each game for $20. What is the cost of game 1?

Answer 1

3$

Step-by-step explanation: :)

Answer 2

$3

Explanation:

Given :

Let game 1 = x ; game 2 = y

4x + 6y = 18 - - - (1)

5x + 5y = 20 - - - (2)

From (2)

x + y = 4

y = 4 - x

Substitute y = 4-x in (1)

4x + 6(4 - x) = 18

4x + 24 - 6x = 18

-2x = 18 - 24

-2x = - 6

x = 6/2

x = 3

Game 1 cost $3