Question

What is 4(y-3)+19=59
A:1/13
B:13
c:-1/13
D:-13

Answer 1

B.) y = 13

Given expression:

`\sf \rightarrow 4(y-3)+19 = 59`

Solving steps:

`\sf \rightarrow 4(y-3)= 59-19`

`\sf \rightarrow 4(y-3)=40`

`\sf \rightarrow y-3=10`

`\sf \rightarrow y=10+3`

`\sf \rightarrow y=13`

Answer 2

B) 13

Explanation:

Given equation:

`4(y-3)+19=59`

Subtract 19 from both sides:

`\implies 4(y-3)+19-19=59-19`

`\implies 4(y-3)=40`

Divide both sides by 4:

`\implies (4(y-3))/(4)=(40)/(4)`

`\implies y-3=10`

Add 3 to both sides:

`\implies y-3+3=10+3`

`\implies y=13`

Check by substituting y = 13 into the original equation:

`\begin{aligned}\implies 4(13-3)+19 & = 4(10)+19\\& = 40+19\\& = 59\end{aligned}`

Hence verifying that y = 13.