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Thermodynamics

Calculate the internal energy and enthalpy variations of an ideal gas (in BTU / lb) when it changes state from 50 °C to 150 °C, with gas properties k = 1.4

User Achekh
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1 Answer

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Answer:

Δu= 29.82 Btu/lb

Step-by-step explanation:

Given that gas temperature changes from 50 °C to 150 °C.

K=1.4

We know that


C_P-C_v=R


C_P/C_v=K

K=1.4 it means that it is air.

We know that for air


C_v=0.71\ KJ/kg.K

We know that internal energy for gas given as


\Delta u=C_v\Delta T KJ/kg

Δu= 0.71 x (150-50) KJ/kg

Δu=71 KJ/kg

We know that

1 KJ/kg=0.42 Btu/lb

So 71 KJ = 29.82 Btu/lb

Δu= 29.82 Btu/lb

User Nebffa
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