122k views
3 votes
Hey everyone !

A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of the largest angle of this triangle measures:
Note: Perimeter = 30


Thank you.​

User Ming Li
by
7.3k points

2 Answers

2 votes

Hello!

A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of the largest angle of this triangle measures:

Note: Perimeter = 30

We have the following data:

p (perimeter) = 14 + 10 + 6 = 30

a = 14 cm

b = 10 cm

c = 6 cm

α (angle) = ?

*** Note: The largest angle (α) is always opposite the larger side.

We apply the data to the Cosine Law, let's see:


a^2 = b^2 + c^2 - 2*b*c*cos\:\alpha


14^2 = 10^2 + 6^2 - 2*10*6*cos\:\alpha


196 = 100 + 36 - 120\:cos\:\alpha


120\:cos\:\alpha = -196 + 100 + 36


120\:cos\:\alpha = -60


cos\:\alpha = (-6\diagup\!\!\!\!0)/(12\diagup\!\!\!\!0) (/6)/(/6)


cos\:\alpha = (-1)/(2)


\boxed{\boxed{cos\:\alpha = 120\º}}\:\:\:\:\:\:\bf\purple{\checkmark}

Answer:

The measure of the largest angle of the triangle is 120º

_______________________


\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

Hey everyone ! A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of-example-1
Hey everyone ! A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of-example-2
User Carherpi
by
9.0k points
3 votes

Answer:

The measure of the largest angle is 120°

Explanation:

Lets explain how to find the measure of an angle from the length of the

sides of the triangle

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

to angle A is BC , the side opposite to angle B is AC and the side

opposite to angle C is AB, So to find measure of angle A use the rule


cos(A)=((AB)^(2)+(AC)^(2)-(BC)^(2))/(2(AB)(AC))

Lets solve the problem

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above


cos(C)=((AC)^(2)+(BC)^(2)-(AB)^(2))/(2(AC)(BC))

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm


cos(C)=((6)^(2)+(10)^(2)-(14)^(2))/(2(6)(10))


cos(C)=(36+100-196)/(120)


cos(C)=(-60)/(120)=-0.5

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C =
cos^(-1)(-0.5)=120

* The measure of the largest angle is 120°

User Marty Lamb
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories