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Hey everyone !

A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of the largest angle of this triangle measures:
Note: Perimeter = 30


Thank you.​

User Ming Li
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2 Answers

2 votes

Hello!

A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of the largest angle of this triangle measures:

Note: Perimeter = 30

We have the following data:

p (perimeter) = 14 + 10 + 6 = 30

a = 14 cm

b = 10 cm

c = 6 cm

α (angle) = ?

*** Note: The largest angle (α) is always opposite the larger side.

We apply the data to the Cosine Law, let's see:


a^2 = b^2 + c^2 - 2*b*c*cos\:\alpha


14^2 = 10^2 + 6^2 - 2*10*6*cos\:\alpha


196 = 100 + 36 - 120\:cos\:\alpha


120\:cos\:\alpha = -196 + 100 + 36


120\:cos\:\alpha = -60


cos\:\alpha = (-6\diagup\!\!\!\!0)/(12\diagup\!\!\!\!0) (/6)/(/6)


cos\:\alpha = (-1)/(2)


\boxed{\boxed{cos\:\alpha = 120\º}}\:\:\:\:\:\:\bf\purple{\checkmark}

Answer:

The measure of the largest angle of the triangle is 120º

_______________________


\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

Hey everyone ! A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of-example-1
Hey everyone ! A triangle has sides measuring 14 cm, 10 cm and 6 cm. The measure of-example-2
User Carherpi
by
5.3k points
3 votes

Answer:

The measure of the largest angle is 120°

Explanation:

Lets explain how to find the measure of an angle from the length of the

sides of the triangle

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

to angle A is BC , the side opposite to angle B is AC and the side

opposite to angle C is AB, So to find measure of angle A use the rule


cos(A)=((AB)^(2)+(AC)^(2)-(BC)^(2))/(2(AB)(AC))

Lets solve the problem

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above


cos(C)=((AC)^(2)+(BC)^(2)-(AB)^(2))/(2(AC)(BC))

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm


cos(C)=((6)^(2)+(10)^(2)-(14)^(2))/(2(6)(10))


cos(C)=(36+100-196)/(120)


cos(C)=(-60)/(120)=-0.5

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C =
cos^(-1)(-0.5)=120

* The measure of the largest angle is 120°

User Marty Lamb
by
4.5k points