Question

A pipe with a diameter of 2 cm is attached to a garden hose with a nozzle. If the velocity of how in the pipe is 2 m/s. what is the velocity of the flow at the nozzle when it is adjusted to have a diameter of 4 mm?

Answer 1

velocity at nozzle is given as

`v_2 = 50 m/s`

Step-by-step explanation:

As we know that volume flow rate through the pipe is always constant

so we can say that volume flow rate is given as

`Q = (dV)/(dt)`

`Q = area * speed`

so we will have

`A_1 v_1 = A_2v_2`

here we have

`A_1 = \pi r_1^2`

`A_2 = \pi r_2^2`

now we have

`\pi (2^2) 2 m/s = \pi (0.4)^2 v_2`

`v_2 = 50 m/s`