Answer:
Maximum speed, v = 36 m/s
Step-by-step explanation:
Given that,
The radius of the curved road, r = 120 m
Road is at an angle of 48 degrees. We need to find the maximum speed of stay on the curve in the absence of friction. On a banked curve, the angle at which it is cant is given by :
![tan\theta=(v^2)/(rg)](https://img.qammunity.org/2020/formulas/physics/college/92sr6rnxze5mczlqbal91eb0y9tnxhwrfy.png)
g is the acceleration due to gravity
![v=√(rg\ tan\theta)](https://img.qammunity.org/2020/formulas/physics/college/qasi2lpr1xe671jff233hbx276k3eqxsbu.png)
![v=√(120* 9.8* \ tan(48))](https://img.qammunity.org/2020/formulas/physics/college/6karua6paz2nr17j8qs1xmbaihwjqnajbf.png)
v = 36.13 m/s
or
v = 36 m/s
So, the maximum speed to stay on the curve in the absence of friction is 36 m/s. Hence, this is the required solution.