Question

The nonvolatile, nonelectrolyte chlorophyll , C55H72MgN4O5 (893.5 g/mol), is soluble in diethyl ether CH3CH2OCH2CH3.

How many grams of chlorophyll are needed to generate an osmotic pressure of 1.19 atm when dissolved in 258 ml of a diethyl ether solution at 298 K.

? grams chlorophyll

Answer 1

The grams of chlorophyll you need are 11,1 g

Step-by-step explanation:

Osmotic pressure is the minimum pressure that you needs to be apply to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. The formula of osmotic pressure is:

π = M×R×T

Where:

M is molar concentration of dissolved species (units of mol/L).

R is ideal gas constant (0.08206 L atm mol⁻¹ K⁻¹, ).

T is the temperature on the Kelvin scale.

In the problem you have:

1,19 atm = M×0,08206 L atm mol⁻¹ K⁻¹×298K

M = 0,048 M

Thus, the grams of chlorophyll you need are:

0,048
`(mol)/(L)` × 0,258 L ×
`(893,5 g)/(mol)` = 11,1 g

I hope it helps!