Question

A fluid that has density of 0.90 g/cm^3 has specific weight of (a) 25.5 Ib/ft^3 (b) 12.5 Ib/ft^3 (c) 20.0 Ib/ft^3 (d) 56.16 Ib/ft^3 (e) none of these

Answer 1

d) 56.16Ib/ft^3[

Step-by-step explanation:

the specific weight is understood as the weight ratio of a body or fluid per unit volume, to find it we must multiply the density by gravity, using the following ecuation:

γ=ρg

where

ρ=density=0.9g/cm^3=900Kg/m^3

g=9.81m/s^2

γ=(9.8)(900)=8820N/m^3

finally we use conversion factors to convert to lb / ft ^ 3

γ=
`(8820 N)/(m^(3) )*(m^(3) )/((3.28ft)^(3) )  *(1Lb)/(4.44N) =56.16Ib/ft^3`

the especific weight of the fluid is d)56.16Ib/ft^3