Answer:
The probability of randomly selecting a student from the class that
owns an Android Phone OR had service with AT&T is 0.6 ⇒ 1st answer
Explanation:
* Lets explain how to solve the problem
- From the Venn-diagram
* There are 6 students own android only
* There are 5 students own iPhone only
* There are 2 students had service with AT&T only
* There are 7 students did not use any of the three above
* There are 4 students use AT&T service and owned android
* There are 6 students use AT&T service and owned iPhone
- Lets find the number of the students in the class
∵ The number of the student in the class is all The number listed above
∴ The number of the student in the class = 6 + 5 + 2 + 7 + 4 + 6
∴ The number of the student in the class = 30
* There are 30 students in the class
- We want to find the probability of the students who owns an android
or had service with AT&T
∵ The number of the students own Android = 6 + 4 = 10
∵ The number of the students use AT&T service = 6 + 4 + 2= 12
∵ The number of the students use both = 4
∴ The number of the students own Android or use AT&T service =
the number of the students own Android + the number of students
use AT&T - the number of students use both
∴ The number of the students own Android or use AT&T service
= 10 + 12 - 4 = 18
∵ Probability = event / total
∴ Probability of the students own android or use AT&T = 18/30 = 0.6
The probability of randomly selecting a student from the class that
owns an Android Phone OR had service with AT&T is 0.6