Question

If all the energy from a 103 W light bulb is emitted at 590.0 nm, what is the energy of each photon in Joule? Planck’s constant is 6.6 x 10-34 J*s and the speed of light is 3.0 x 108 m/s.

Answer 1

Energy of each photon is given by
`0.0335* 10^(-17)j`

Step-by-step explanation:

We have given wavelength of light
`\lambda =590nm=590* 10^(-9)m`

Speed of light
`c=3* 10^8m/sec`

Plank's constant
`h=6.6* 10^(-34)j-s`

We know that energy of photon is given by
`E=h\\u =(hc)/(\lambda )`

So energy is given by

`E=h\\u =(hc)/(\lambda )=(6.6* 10^(-34)* 3* 10^8)/(590* 10^(-9))=0.0335* 10^(-17)j`