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If all the energy from a 103 W light bulb is emitted at 590.0 nm, what is the energy of each photon in Joule? Planck’s constant is 6.6 x 10-34 J*s and the speed of light is 3.0 x 108 m/s.

User Binaya
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1 Answer

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Answer:

Energy of each photon is given by
0.0335* 10^(-17)j

Step-by-step explanation:

We have given wavelength of light
\lambda =590nm=590* 10^(-9)m

Speed of light
c=3* 10^8m/sec

Plank's constant
h=6.6* 10^(-34)j-s

We know that energy of photon is given by
E=h\\u =(hc)/(\lambda )

So energy is given by


E=h\\u =(hc)/(\lambda )=(6.6* 10^(-34)* 3* 10^8)/(590* 10^(-9))=0.0335* 10^(-17)j

User Rob Cameron
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