Question

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = y minus 3 equals StartFraction one-half EndFraction left-parenthesis x minus 1 right-parenthesis.(x – 1). What is the slope-intercept form of the equation for this line?

y = y equals StartFraction one-half EndFraction x plus 2.x + 2
y = y equals StartFraction one-half EndFraction x minus 4.x – 4
y = y equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction.x +
y = y equals StartFraction one-half EndFraction x minus StartFraction 7 Over 2 EndFraction.x –

Answer 1

C on edge

Explanation:

Answer 2

`y=(1)/(2)x+(5)/(2)`

Explanation:

we have

`y-3=(1)/(2)(x-1)`

Convert to slope intercept form

`y=mx+b`

Isolate the variable y

Distribute in the right side

`y-3=(1)/(2)x-(1)/(2)`

Adds 3 both sides

`y=(1)/(2)x-(1)/(2)+3`

`y=(1)/(2)x+(5)/(2)`

therefore

y = equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction