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The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = y minus 3 equals StartFraction one-half EndFraction left-parenthesis x minus 1 right-parenthesis.(x – 1). What is the slope-intercept form of the equation for this line?

y = y equals StartFraction one-half EndFraction x plus 2.x + 2
y = y equals StartFraction one-half EndFraction x minus 4.x – 4
y = y equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction.x +
y = y equals StartFraction one-half EndFraction x minus StartFraction 7 Over 2 EndFraction.x –

2 Answers

3 votes

Answer:

C on edge

Explanation:

User Nagarajan M
by
7.8k points
7 votes

Answer:


y=(1)/(2)x+(5)/(2)

Explanation:

we have


y-3=(1)/(2)(x-1)

Convert to slope intercept form


y=mx+b

Isolate the variable y

Distribute in the right side


y-3=(1)/(2)x-(1)/(2)

Adds 3 both sides


y=(1)/(2)x-(1)/(2)+3


y=(1)/(2)x+(5)/(2)

therefore

y = equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction

User GeoffDS
by
7.7k points

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