Answer:
15.
![\left\{\begin{array}{l}x+y=50\\0.2x+0.1y=6\end{array}\right.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vea5omeh9f4dgva0p82vmi8ovvi7xloahl.png)
16. 10 ml of 20% saline and 40 ml of 10% saline
Explanation:
A chemist takes x ml of 20% saline and y ml of 10% saline. In total, he takes
x + y ml that is 50 ml, so
![x + y = 50.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1r7ucjei38au74sq7wsb5fvhjbclvai0lx.png)
There are
ml of salt in x ml of 20% saline and
ml of salt in 10% saline. There are
ml of salt in 50 ml of 12% saline. Thus,
![0.2x+0.1y=6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/chqtxh8or2iv7ya1m8ty5uxvmmqbymk8pk.png)
15. We get the system of two equations:
![\left\{\begin{array}{l}x+y=50\\0.2x+0.1y=6\end{array}\right.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vea5omeh9f4dgva0p82vmi8ovvi7xloahl.png)
16. Solve this system. From the first equation:
![x=50-y](https://img.qammunity.org/2020/formulas/mathematics/high-school/cxwh0aarzu01zge8a0weac3aqptwiaka9m.png)
Substitute it into the second equation:
![0.2(50-y)+0.1y=6\\ \\10-0.2y+0.1y=6\\ \\-0.1y=6-10\\ \\-0.1y=-4\\ \\y=40\\ \\x=50-y=50-40=10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gzf4knc1wrhi6abz3d0805jhfn5do8hpvi.png)