The value of x in ln(3x + 2) = 4 is
![\bold{(e^(4) - 2)/(3)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ru3b8m15yf7lhek2w30te1g0gwaz5xgqb.png)
Answer:
Option a
Solution:
From question, given that ln(3x + 2) = 4
ln(3x + 2) = 4 ----- eqn 1
By raising “e” to the power of both sides of equation, the above equation becomes
![e^(\ln (3 x + 2)) = e^(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z33npn6ngje911z0lvcpyjyw6ele8ed3m8.png)
“ln” and “e” cancel out each other in left hand side of above equation. Hence we get
![3x + 2 = e^(4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/45hse1kwhrtmm14rxt31k20zyncm0sqmbr.png)
Rearranging the terms, the above equation becomes,
![3 x=e^(4)-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ttxu8hxf1ioecitqs3ay7f9yyr3q0usz07.png)
x =
![(e^(4) - 2)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/p49blgzebbx5hu04ev63g5q71v3vwjynro.png)
Thus the value of x in ln(3x + 2) = 4 is
![\bold{(e^(4) - 2)/(3)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ru3b8m15yf7lhek2w30te1g0gwaz5xgqb.png)