Question

Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal conductivity is 13 W/m-K, the surface area is 5 m2, and the surface temperatures are 14 °C and 93 °C. Report your answer in Watts.

Answer 1

Step-by-step explanation:

The given data is as follows.

Thickness (dx) = 0.87 m, thermal conductivity (k) = 13 W/m-K

Surface area (A) = 5
`m^(2)`,
`T_(1) = 14^(o)C`

`T_(2) = 93^(o)C`

According to Fourier's law,

Q =
`-kA (dT)/(dx)`

Hence, putting the given values into the above formula as follows.

Q =
`-kA (dT)/(dx)`

=
`-13 W/m-k * 5 m^(2) * ((14 - 93))/(0.87 m)`

= 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.