1 Answer

Keeley · Answer 1 · 2020-03-10T20:35:25+0000

Answer: The molarity of sulfuric acid solution is 2.3 M

Step-by-step explanation:

The relationship between specific gravity and density of a substance is given as:

$\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}$

Specific gravity of sulfuric acid solution = 1.13

Density of water = 1.00 g/mL

Putting values in above equation we get:

$1.13=\frac{\text{Density of sulfuric acid solution}}{1.00g/mL}\\\\\text{Density of sulfuric acid solution}=(1.13* 1.00g/mL)=1.13g/mL$

We are given:

20% (m/m) sulfuric acid solution. This means that 20 g of sulfuric acid is present in 100 g of solution

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of solution = 1.13 g/mL

Mass of Solution = 100 g

Putting values in above equation, we get:

$1.13g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=(100g)/(1.13g/mL)=88.5mL$

$\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (sulfuric acid) = 20 g

Molar mass of sulfuric acid = 98 g/mol

Volume of solution = 88.5 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=(20g* 1000)/(98g/mol* 88.5mL)\\\\\text{Molarity of solution}=2.3M$

Hence, the molarity of sulfuric acid solution is 2.3 M

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