Question

A triangular prism and two nets are shown:

A right triangular prism is shown with two nets. The triangular base of the prism has height 5 inches, base 12 inches, and hypotenuse 13 inches. The length of the prism is 15 inches. Net A has 3 rectangles having dimensions 5 by 15, 15 by 12, and 15 by 13, and two triangles having legs 5 inches and 12 inches. Net B has 3 rectangles having dimensions 5 by 13, 13 by 12, and 13 by 15, and two triangles having legs 5 inches and 12 inches.

Which is the correct net of the prism and what is the surface area of the prism?

Net B with 420 square inches
Net B with 500 square inches
Net A with 510 square inches
Net A with 450 square inches

Answer 1

Net for the prism will have 3 rectangles with dimensions 5 by 15, 12 by 15 , and 13 by 15, and 2 triangles with legs 5 inches and 12 inches.

The correct net is net a.

Surface area = sum of areas of the three rectangles and sum of the two triangles.

SA = (5 x 15) + (12 x 15) + (13 x 15) + (5 x 12) = 75 + 180 + 195 + 60 = 510 square inches.

Explanation:

Hope this helped