Question

Perform the following unit conversions:

a)

60 feet of water to Pa

b)

220 psi to lbf/ft^2

c)

120 torr to Pa

d)

1.0 atm to inches of glycerin

e)

1050 mm Hg to lbf/ft^2

Answer 1

(a) The 60 feet of water is equal to 179344.2 Pa.

(b) The 220 psi is equal to
`31680lbf/ft^2`

(c) The 120 torr is equal to 15998.6 Pa.

(d) The 1.0 atm to inches of glycerin is equal to 323.07 inches.

(e) The 1050 mm Hg is equal to
`376.95lbf/ft^2`

Explanation :

(a) The conversion used from feet to pascal is:

`1\text{ feet}=2989.07Pa`

As we are given that 60 feet of water. Now we have to convert into Pa.

As,
`1\text{ feet}=2989.07Pa`

So,
`60\text{ feet}=\frac{60\text{ feet}}{1\text{ feet}}* 2989.07Pa=179344.2Pa`

The 60 feet of water is equal to 179344.2 Pa.

(b) The conversion used from
`psi` to
`lbf/ft^2` is:

`1\text{ psi}=144lbf/ft^2`

As we are given that 220 psi. Now we have to convert into
`lbf/ft^2`.

As,
`1\text{ psi}=144lbf/ft^2`

So,
`220\text{ psi}=\frac{220\text{ psi}}{1\text{ psi}}* 144lbf/ft^2=31680lbf/ft^2`

The 220 psi is equal to
`31680lbf/ft^2`

(c) The conversion used from torr to pascal is:

`1\text{ torr}=133.322Pa`

As we are given that 120 torr. Now we have to convert into Pa.

As,
`1\text{ torr}=133.322Pa`

So,
`120\text{ torr}=\frac{120\text{ torr}}{1\text{ torr}}* 133.322Pa=15998.6Pa`

The 120 torr is equal to 15998.6 Pa.

(d) 1.0 atm to inches of glycerin

Formula used :
`P=\rho gh`

where,

P = pressure of glycerin = 1.0 atm = 101325 Pa

g = acceleration due to gravity =
`9.8m/s^2`

`\rho` = density of glycerin =
`1260kg/m^3`

Now put all the given values in above formula, we get:

`101325Pa=(1260kg/m^3)* (9.8m/s^2)* h`

`h=8.206(Pa.m^2s^2)/(kg)=8.206m=323.07\text{ inches}`

Conversion used :

`1Pa=(kg)/(ms^2)\\\\1m=39.37inches`

The 1.0 atm to inches of glycerin is equal to 323.07 inches.

(e) The conversion used from
`psi` to
`lbf/ft^2` is:

`1\text{ mmHg}=0.359lbf/ft^2`

As we are given that 1050 mmHg. Now we have to convert into
`lbf/ft^2`.

As,
`1\text{ mmHg}=0.359lbf/ft^2`

So,
`1050\text{ mmHg}=\frac{1050\text{ mmHg}}{1\text{ mmHg}}* 0.359lbf/ft^2=376.95lbf/ft^2`

The 1050 mm Hg is equal to
`376.95lbf/ft^2`