Question

Find the work done using data from the PV plot for an isothermal system.

P1= 100 kPa, P2= 300 kPa

V1= 25 m^3 , V2= 10 m^3

B.) Is the work done by the system or on the system?

Answer 1

W = - 500 KJ

∴ the work is done on the system

Step-by-step explanation:

isothermal system:

∴ ΔU = 0; ⇒ Q = W

∴ W = P1V1 -P2V2

⇒ W = ((100KPa)*(25m³)) - ((300KPa)*(10m³))

⇒ W = 2500KPa.m³ - 3000KPa,m³

⇒ W = - 500 KPa.m³ = - 500 KJ

∴ W (-) the work is done on the system