Question

Write an equation of the line that passes through (−3,7) and is perpendicular to the line y=−2x−5.

Answer 1

The desired equation is

y = (1/2)x + 17/2

Explanation:

The slope of the perpendicular line is the negative reciprocal of -2: m = 1/2.

Start with y = mx + b.

Substituting 7 for y, 1/2 for m and -3 for x, we get:

7 = (1/2)(-3) + b. Then 7 = -3/2 + b, so that b = 17/2.

The desired equation is

y = (1/2)x + 17/2

Answer 2

Explanation:

an equation is : Use the point-slope formula.

y - y_1 = m(x - x_1) ; m : the slope when : x_1 = -3 and y_1 = 7

- 2 ×m = - 1 because this line is perpendicular to the line y= -2x-5 when the slope is -2

so : m= 1/2

an equation is : y - 7 =(1/2)(x+3)