Question

To dilute a HCl solution from 0.400 M to 0.100 M the final volume must be

Answer 1

Step-by-step explanation:

Molarity of HCl ,
`M_1= 0.400 M`

Volume of the HCl solution =
`V_1=500mL` (assume)

Molarity of HCl after dilution
`M_1= 0.100 M`

Volume of new HCl solution =
`V_2`

`M_1V_1=M_2V_2`

`0.400 M* 500 mL=0.100 M* V_2`

`V_2=(0.400 M* 500 mL)/(0.100 M)=2000 mL`

`(V_1)/(V_2)=(500 mL)/(2000 mL)`

`V_2=4* V_1`

In order to dilute a HCl solution from 0.400 M to 0.100 M the final volume must be 4 times the initial volume of 0.400 M HCl solution .

Answer 2

The final volume must be 400 mL.

Step-by-step explanation:

Let us assume the Initial volume as 100ml

Using dilution factor formula

`\\$M_(1) * V_(1)=M_(2) * V_(2)$\\\\$0.400 M * 100 m l=0.100 M * V_(2)$`

So,

`$V_(2)=(0.400 M * 100 m l)/(0.100 M)=400 m l$`

Thus, the final volume must be 400 mL.