Question

The force of attraction between a -130.0 C and +180.0 C charge is 8.00 N. What is the separation between these two charges in meter rounded to three decimal places? (k = 1/470 - 9.00 10°N.m2/C2 1uC = 106C)

Answer 1

Answer with Explanation:

The force of attraction between 2 charges of magnitude
`q_1,q_2` separated by a distance 'r' is given by

`F=(1)/(4\pi \epsilon _o)(q_1* q_2)/(r^2)=k(q_1* q_2)/(r^2)`

where

`\epsilon _o` is a constant known as permitivity of free space

`k=9* 10^(9)Nm^2/C^2`

Applying the given values in the above relation we get

`8=9* 10^(9)* (130* 180)/(r^(2))\\\\r^(2)=(9* 10^(9)* 130* 180)/(8)\\\\r^(2)=26325* 10^(9)\\\\\therefore r=\sqrt{26325* 10^(9)}=5.131* 10^(6)meters`