Final answer:
To determine how many cars of each type will be purchased, we can set up a system of equations using the given information. Solving this system of equations will give us the values of x, y, and z, which represent the number of compact, intermediate-size, and full-size cars purchased. The solution is 50 compact cars, 25 intermediate-size cars, and 25 full-size cars.
Step-by-step explanation:
To solve this problem, we can set up a system of equations using the given information.
Let x be the number of compact cars, y be the number of intermediate-size cars, and z be the number of full-size cars.
We can write the following equations:
1) x + y + z = 100 (Total number of cars)
2) 16000x + 24000y + 32000z = 2080000 (Total cost)
3) x = 2y (Twice as many compacts as intermediates)
Solving this system of equations will give us the values of x, y, and z.
Substituting x from equation 3) into equation 1), we get:
2y + y + z = 100
3y + z = 100
Substituting x from equation 3) into equation 2), we get:
16000(2y) + 24000y + 32000z = 2080000
32000y + 24000y + 32000z = 2080000
56000y + 32000z = 2080000
Now we have a system of two equations:
3y + z = 100
56000y + 32000z = 2080000
Solving these equations will give us the values of x, y, and z.
Using any method of solving systems of equations, we find that y = 25 and z = 25.
Substituting these values back into equation 3) gives us x = 50.
Therefore, 50 compact cars, 25 intermediate-size cars, and 25 full-size cars will be purchased.