Final answer:
The average rate of the reaction in terms of the disappearance of reactant A between time = 0 s and time = 20 s is -0.0024 M/s.
Step-by-step explanation:
The rate of a chemical reaction can be expressed as the change in concentration of a reactant over time. In this case, we are looking at the average rate of the reaction in terms of the disappearance of reactant A between time = 0 s and time = 20 s for the reaction 2A+3B→3C+2D. The concentrations of reactant A at three different time intervals are given: [A] = 0.1200 M at time = 0 s, [A] = 0.0720 M at time = 20 s, and [A] = 0.0540 M at time = 40 s. To calculate the average rate of reaction in terms of the disappearance of reactant A between time = 0 s and time = 20 s, we can use the formula:
Average rate = (change in concentration of A) / (change in time)
To calculate the change in concentration of A, we subtract the initial concentration from the final concentration: 0.0720 M - 0.1200 M = -0.0480 M. The change in time is simply 20 s. Plugging these values into the formula, we get:
Average rate = (-0.0480 M) / (20 s) = -0.0024 M/s
Therefore, the average rate of the reaction in terms of the disappearance of reactant A between time = 0 s and time = 20 s is -0.0024 M/s.