Question

A tall tube is evacuated, and its stopcock closed. The open end of the tube is immersed into a container of water (density 103 kg/m3) that is open to the atmosphere (pressure 105 N/m2). When the stopcock is opened, how far up the tube will the water rise? A.1 m B.5 m C.10 m D.20 m

Answer 1

Step-by-step explanation:

It is given that,

Density of water,
`d=10^3\ kg/m^3`

Atmospheric pressure,
`P=10^5\ N/m^2`

The pressure exerted at a height h is given by :

`P=d* g* h`

g is acceleration due to gravity

`h=(P)/(dg)`

`h=(10^5)/(10^3* 9.8)`

h = 10.2 meters

or

h = 10 meters

So, the water will rise to a height of 10 meters. Hence, this is the required solution.