Question

A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 7.20 m radius, at how many revolutions per minute are the riders subjected to a centripetal acceleration equal to that of gravity?

Answer 1

Answer:1.16 rad/s

Step-by-step explanation:

Given

radius of circular path(r)=7.20 m

let
`\omega`be the angular velocity of ride

and centripetal acceleration is given by
`\omega ^2r`

which should be equal to gravity(g)

`\omega ^2r=g`

`\omega ^2=(g)/(r)`

`\omega =\sqrt{(g)/(r)}`

`\omega =√(1.3625)`

`\omega =1.16 rad/s`