Question

How do i find the limit of number 2?

Answer 1

The numerator has degree 1, and the denominator has degree 2. For large
`x`, the denominator will dominate, so the limit would be 0.

Put another way, we have

`(2x+7)/(x^2-x)=\frac{\frac2x+\frac7{x^2}}{1-\frac1x}`

and each fraction with
`x` will aproach 0. The numerator itself approaches 0 while the denominator approaches 1, so the overall limit is 0.