Question

Emily went to a toy store that was selling two Nintendo DS games and four Wii games for a total of $240. Emily bought three DS games and two Wii games and spent $160. What was the price of one Wii game?

Answer 1

The price of one Wii game is $50

Explanation:

Let the cost of 1 Nintendo DS games be x

Cost of 2 Nintendo DS games = 2x

Cost of 3 Nintendo DS games = 3x

Let the cost of 1 Wii game be y

Cost of 4 Wii game = 4y

Cost of 2 Wii game = 2y

Now we are given that Emily went to a toy store that was selling two Nintendo DS games and four Wii games for a total of $240

So,
`2x+4y = 240` --- A

Emily bought three DS games and two Wii games and spent $160

So,
`3x+2y = 160` ---- B

Plot lines A and B on graph . Intersection point will provide the solution .

`2x+4y = 240` -- Green

`3x+2y = 160` -- Blue

Intersection Point = (20,50)

So, Cost of 1 Nintendo DS games = $20

Cost of 1 Wii game = $50

Hence the price of one Wii game is $50

Answer 2

The price of one WII game is $50.

What is the simultaneous equation that can be used to represent this question:

2n + 4w = 240 equation 1

3n + 2w = 160 equation 2

Where:

n = price of nintendo games

w = price of wii game

What is the price of one wii game?

In order to determine the required game, multiply equation 1 by 2 and equation 2 by 3

6n + 12w = 720 equation 3

6n + 4w = 320 equation 4

Subtract equation 4 from 3

8w = 400

w = 50