Question

An engineer is undertaking some reconnaissance by pacing on a construction site. The engineer takes 26 steps per 20m, the ground he is walking on has a vertical slope angle of 6. The engineer takes 152 steps. How far has he travelled horizontally (in metres)?(only enter numeric answer to 2 decimal places, no alpha characters)

Answer 1

Thus the distance traveled horizontally is 116.28 m

Solution:

As per the question:

Distance covered in 26 steps = 20 m

Thus

Distance covered in one step, step size =
`(20)/(26)`

Total steps taken = 152

Now, the distance covered in 152 steps =
`one step size* 152`

The distance covered in 152 steps, D =
`(20)/(26)* 152 = 116.92 m`

The above distances are on a slope of
`6^(\circ)` above horizontal.

Thus the horizontal component of this distance is given by:

`d_(H) = Dcos6^(\circ)`

where

`d_(H)` = horizontal component of distance, D

`d_(H) = 116.92cos6^(\circ) = 116.28 m`