Answer:
37357 sec
or 622 min
or 10.4 hrs
Step-by-step explanation:
GIVEN DATA:
Lifting weight 80 kg
1 cal = 4184 J
from information given in question we have
one lb fat consist of 3500 calories = 3500 x 4184 J
= 14.644 x 10^6 J
Energy burns in 1 lift = m g h
= 80 x 9.8 x 1 = 784 J
lifts required
![= ((14.644 x 10^6))/(784)](https://img.qammunity.org/2020/formulas/physics/college/5i3wg7bk3rizkz4bj9i82p6n2w06zjkseg.png)
= 18679
from the question,
1 lift in 2 sec.
so, total time = 18679 x 2 = 37357 sec
or 622 min
or 10.4 hrs