Answer: The molecular formula of glucose is
![C_6H_(12)O_6](https://img.qammunity.org/2020/formulas/chemistry/middle-school/95ic0dz9zeqrxzk62c1iqrxwob63enydn6.png)
Step-by-step explanation:
We are given:
Empirical formula of the compound =
![CH_2O](https://img.qammunity.org/2020/formulas/chemistry/college/lbz44ia4c9vxtloafka3j7di81r4kakf3h.png)
Empirical mass of the compound =
![[(1* 12)+(2* 1)+(1* 16)]=30g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/u1qhyd04wca1pjze6gvhoypbor1hskf0b5.png)
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is:
![n=\frac{\text{Molecular mass}}{\text{Empirical mass}}](https://img.qammunity.org/2020/formulas/chemistry/college/crwo18dml82d9bnvvo80b0pz6zb4di82wu.png)
We are given:
Mass of molecular formula = 180.12 g/mol
Mass of empirical formula = 30 g/mol
Putting values in above equation, we get:
![n=(180.12g/mol)/(30g/mol)=6](https://img.qammunity.org/2020/formulas/chemistry/college/cl8grijtqxln48w4uuxedlpqbua2e20bzu.png)
Multiplying this valency by the subscript of every element of empirical formula, we get:
![C_((1* 6))H_((2* 6))O_((1* 6))=C_6H_(12)O_6](https://img.qammunity.org/2020/formulas/chemistry/college/dl9y7b6fyeqlmwzvc1z4qsfbd3e8jb53ob.png)
Hence, the molecular formula of glucose is
![C_6H_(12)O_6](https://img.qammunity.org/2020/formulas/chemistry/middle-school/95ic0dz9zeqrxzk62c1iqrxwob63enydn6.png)