Question

Two equal charges with magnitude Q and Q experience a force of 12.3442 when held at a distance r. What is the force between two charges of magnitude 2*Q and 2*Q when held at a distance r/2.?

Answer 1

Answer:197.504 N

Step-by-step explanation:

Given

Two Charges with magnitude Q experience a force of 12.344 N

at distance r

and we know Electrostatic force is given

`F=(kq_1q_2)/(r^2)`

`F=(kQ\cdot Q)/(r^2)`

`F=(kQ^2)/(r^2)`

Now the magnitude of charge is 2Q and is at a distance of
`(r)/(2)`

`F'=(k2Q\cdot 2Q)/((r^2)/(2^2))`

F'=16F

F'=197.504 N