Question

A charge q1= 3nC and a charge q2 = 4nC are located 2m apart. Where on the line passing through these charges is the total electric field zero?

Answer 1

Step-by-step explanation:

Electric field due to a charge Q at a point d distance away is given by the expression

E = k Q / d , k is a constant equal to 9 x 10⁹

Field due to charge = 3 X 10⁻⁹ C

E = E =
`(9* 10^9*3*10^(-9))/(d^2)`

Field due to charge = 4 X 10⁻⁹ C

`E = [tex](9* 10^9*4*10^(-9))/((2-d)^2)`

These two fields will be equal and opposite to make net field zero

`(9* 10^9*3*10^(-9))/(d^2)` =
`[tex](9* 10^9*4*10^(-9))/((2-d)^2)`[/tex]

`(3)/(d^2) =(4)/((2-d)^2)`

`(2-d)/(d) =(2)/(1.732)`

d = 0.928