Answer: Yes , the points (-4,-1), (2,1) and (11,4) are collinear.
Explanation:
We know that if three points
and
are collinear, then their area must be zero.
The area of triangle passes through points
and
is given by :-
![\text{Area}=(1)/(2)|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|](https://img.qammunity.org/2020/formulas/mathematics/college/qo1benuqzu4w72m54ni7ci5wir3x6o8dxy.png)
Given points : (-4,-1), (2,1) and (11,4)
Then, the area of ΔABC will be :-
![\text{Area}=(1)/(2)|-4(1-4)+(2)(4-(-1))+(11)(-1-1)|\\\\\Rightarrow\text{Area}=(1)/(2)|-4(-3)+(2)(5)+(11)(-2)||\\\\\Rightarrow\text{Area}=(1)/(2)|12+10-22|\\\\\Rightarrow\text{Area}=(1)/(2)|0|=0](https://img.qammunity.org/2020/formulas/mathematics/college/d876j9qac20xdox464p2s6t4vssqlocpkn.png)
Hence, the points (-4,-1), (2,1) and (11,4) are collinear.