Question

Write a program that continues to read positive integer values until user enters a negative value. The program should print average of entered values, maximum value and minimum value

Answer 1

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

int main()

{

// variable

int n;

int mi=INT_MAX;

int mx=INT_MIN;

double avg;

int count=0;

double sum=0;

cout<<"enter a positive integer(Negative number to stop):";

// read the input first time

cin>>n;

// read the input until user enter a negative number

while(n>=0)

{

// calculate minimum

if(n<mi)

mi=n;

// calculate maximum

if(n>mx)

mx=n;

// count of entered numbers

count++;

// total sum of all number

sum=sum+n;

cout<<"enter a positive integer(Negative number to stop):";

// read the input again

cin>>n;

}

// calculate the average

avg=sum/count;

// print the average

cout<<"average of "<<count<<" number is:"<<avg<<endl;

// print the maximum

cout<<"maximum of all number is:"<<mx<<endl;

// print the minimum

cout<<"minimum of all number is:"<<mi<<endl;

return 0;

}

Step-by-step explanation:

Declare and initialize "mi" with maximum integer value.Similarly "mx" with minimum integer value.Read user input until user enter a negative number.Add all the number to variable "sum" and keep count of positive number entered with "count".When user enter a negative number then it will stop taking input and calculate average of all number by dividing sum with count. Also it will check for each and find the maximum and minimum among the all input.

Output:

enter a positive integer(Negative number to stop):23

enter a positive integer(Negative number to stop):10

enter a positive integer(Negative number to stop):34

enter a positive integer(Negative number to stop):22

enter a positive integer(Negative number to stop):5

enter a positive integer(Negative number to stop):-2

average of 5 number is:18.8

maximum of all number is:34

minimum of all number is:5