Question

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz. What is the period of the crystal's motion?

Answer 1

Time period,
`T=3.05* 10^(-5)\ s`

Step-by-step explanation:

Given that,

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz, f = 32768 Hz

We need to find the period of the crystal's motion. The relationship between the frequency and the time period is given by :

`T=(1)/(f)`

T is the time period of the crystal's motion.

Time period is given by :

`T=(1)/(32768)`

`T=3.05* 10^(-5)\ s`

So, the time period of the crystal's motion is
`3.05* 10^(-5)\ s`. Hence, this is the required solution.