Question

If you have 0.08157 moles of Al(CIO4) 3... a) How many moles of Al ions do you have? b) How many moles of CIO4 ions do you have? c) How many moles of oxygen atoms do you have? 3+

Answer 1

Answer: a) 0.08157 moles of
`Al^(3+)`

b) 0.24471 moles of
`ClO_4^(-)`

c) 0.97884 moles of oxygen atoms

Explanation:-

The dissociation of the given compound is shown by the balanced equation:

`Al(ClO_4)_3\rightarrow Al^(3+)+3ClO_4^(-)`

According to stoichiometry:

a) 1 mole of
`Al(ClO_4)_3` produces 1 mole of
`Al^(3+)`

Thus 0.08157 mole of
`Al(ClO_4)_3` produces=
`(1)/(1)* 0.08157=0.08157moles` of
`Al^(3+)`

b) 1 mole of
`Al(ClO_4)_3` produces 3 moles of
`ClO_4^(-)`

Thus 0.08157 mole of
`Al(ClO_4)_3` produces=
`(3)/(1)* 0.08157=0.24471moles` of
`ClO_4^(-)`

c) 1 mole of
`Al(ClO_4)_3` produces 12 moles of oxygen atoms

Thus 0.08157 mole of
`Al(ClO_4)_3` produces=
`(12)/(1)* 0.08157=0.97884moles` of oxygen atoms