Question

A particle moves with a constant speed of 6 m/s along a circular path of a radius of 4 m. What is the magnitude of its acceleration. Do not include units in your answer, assumed unit are m/s2.

Answer 1

Acceleration in circular path will be 9

Step-by-step explanation:

We have given speed of the particle in circular path = 6 m/sec

Radius of the circular path = 4 m

We have to find the centripetal acceleration
`a_c`

We know that centripetal acceleration is given by
`a_c=(v^2)/(r)=(6^2)/(4)=9`

As in question it is given that don't include the unit

So acceleration will be 9