Answer:
T=5.3° C
Step-by-step explanation:
Given that
Power input to the pump = 2 KW
Building loses heat rate = 0.5 KW/C
So rate of heat transfer = 0.5(273+30-T)
rate of heat transfer = 0.5(303-T)
T=Ambient temperature
Building temperature = 30° C
We know that ,heat pump is used to heat the building.
COP of pump = 0.5 COP of Carnot heat pump
![COP\ of\ Carnot\ heat\ pump=(273+30)/(303-T)](https://img.qammunity.org/2020/formulas/engineering/college/45ewx6zbabmzrir8uyq4j0abzk4vejixbx.png)
-----1
And also
----2
So from now equation 1 and 2
![(303-T)/(4)=(1)/(2)* (303)/(303-T)](https://img.qammunity.org/2020/formulas/engineering/college/qsx9y5ivuzzauo1pcjm9emxiwn06wyoq2r.png)
So T= 278.38 K=5.3° C
T=5.3° C
Ambient temperature =5.3° C.