Question

A centrifuge in a medical labarotary rotates at an

angularspeed of 3600 rev/min. When switch off, it rotates
through50.0 revolutions before coming to rest. Find the
constantangular acceleration of the centrifuge.

Answer 1

angular acceleration = - 217.5 rad/s²

Step-by-step explanation:

given data

angular speed = 3600 rev/min

rotate = 50 revolution

to find out

angular acceleration

solution

we know here no of rotation n = 3600 rev/min i.e 60 rev/s

so initial angular velocity will be ω(i) = 2π× n

ω(i) = 2π× 60 = 376.9 rad/s

and

final angular velocity will be ω(f) = 0

so

angular displacement will be = 2π × 52 = 326.56 rad

and angular acceleration calculated as

angular acceleration =
`(\omega(f)^2-\omega(i)^2)/(2*angular displacement)`

put here value

angular acceleration =
`(-376.9^2)/(326.56)`

angular acceleration = - 217.5 rad/s²