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Let S = {1, 3, 5, 7}. Define the set J = j ∈ S. List the elements of J.

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Answer: Elements of J = {-9,7,39,87}

Explanation:

Since we have given that

S={1,3,5,7}

Define of set J is given by


J=\{2j^2-11:j\epsilon S\}

Put j = 1


2j^2-11\\\\=2-11\\\\=-9

Put j = 3


2(3)^2-11\\\\=2* 9-11\\\\=18-11\\\\=7

Put j = 5


2(5)^2-11\\\\=2* 25-11\\\\=50-11\\\\=39

Put j = 7


2(7)^2-11\\\\=2* 49-11\\\\=98-11\\\\=87

Hence, elements of J = {-9,7,39,87}

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