Question

A cube with sides of area 48 cm^2 contains a 28.7 nanoCoulomb charge. Find the flux of the electric field through the surface of the cube in unis of Nm^2/C.

Please conceptually explain this question answer to me! Thanks!!

Answer 1

The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].

Step-by-step explanation:

Given that,

Area of cube = 48 cm²

Charge = 28.7 nC

We need to calculate the flux of the electric field through the surface

Using formula Gauss's law

The electric flux through any closed surface,

`\phi =(q)/(\epsilon_(0))`

Where, q = charge

Put the value into the formula

`\phi=(28.7*10^(-9))/(8.85*10^(-12))`

`\phi =3.24*10^(3)\ Nm^/C`

Hence, The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].