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Show that 2 - sqrt(2) is irrational

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Answer:

This proof can be done by contradiction.

Let us assume that 2 - √2 is rational number.

So, by the definition of rational number, we can write it as


2 -√(2) = (a)/(b)

where a & b are any integer.


√(2) = 2 - (a)/(b)

Since, a and b are integers
2 - (a)/(b) is also rational.

and therefore √2 is rational number.

This contradicts the fact that √2 is irrational number.

Hence our assumption that 2 - √2 is rational number is false.

Therefore, 2 - √2 is irrational number.

User Stephen Chung
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